# Line slope calculator 7x+4y=32

**Straight line given by points A[0; 8] and B[4; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.75x+8

**Canonical form of the line equation:**7x+4y-32 = 0

**Parametric form of the line equation:**

x = 4t

y = -7t+8 ; t ∈ R

**Slope:**m = -1.75

**Slope angle of line: φ =**-60°15'18″ = -1.0517 rad

**X intercept:**x

_{0}= 4.5714

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 3.9691

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(4; -7)

**Normal vector: n =**(7; 4)

**Midpoint of the segment AB: M =**[2; 4.5]

**Perpendicular Bisector equation:**4x-7y+23.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (4; 1) ; |OB| = 4.1231**

**Scalar product OA .OB = 8**

**Angle ∠ AOB = 75°57'50″ = 1.3258 rad**